Erausre resulient (9,7)-code

 

 

Given are:

-         packets of identical size, divisible by 3, minimum 3 bits

-         7 information packets

-         2 redundant packets

-         Reception of any 7 packets must restore the information

 

 

Let the information packets be

where ,  and are the first, second and third portions of the same packet

 

The first redundant packet is a simple XOR checksum of all information packets

where the summation is by XOR

 

The second redundant packet is:

where , such that ,  and  are XOR results of some combinations of x, y and z and thus f can be represented by a 3 by 3 binary matrix.

 

Any  is invertible, i.e. there exists , such that .

There are 168 invertible functions and thus invertible  packets (see here).

 

The case is obvious, if we have lost one information with one redundant packet.

 

If we have lost two information packets i and j then from the redundant packets we can obtain these two packets:

 

+

+

 

The second one can be transformed to

+

 

Note that is also invertible for any i and j

 

By XOR-ing the two packets we obtain

+

 

And if the result is invertible then we can restore  and consecutively also

 

Thus we need to chose the set of f functions such that the following is ensured:

if F and F

then +1F

 

For all  elements of F we can built a set of pairs E such that if fF, gF and gF, then (f , g)E. Thus we have a graph G(F,E). The size of the max clique of G is the length of the maximal codeword minus 2.

 

The max-clique size is 7, thus we can construct (9,7)-code with this method.

 

Here is a corresponding AMPL program and data. The max-clique here is the same as the one needed for the construction of (9,2)-code.

 

 

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US – Mirror

CH – Mirror

 

© 2005, Switzernet (www.switzernet.com)

 

 

Relevant links:

 

051025-erasure-resilient

051027-erasure-9-2-resilient

051031-erasure-10-3-resilient